XDocument xDoc = XDocument.Load(_filePath);
XElement root = xDoc.Root;
root.Add(new XElement("MenuItem",
new XElement("Name", "ttttt"),
new XElement("Url", "www.this.com"),
new XElement("Images",
new XElement("image", "img1"),
new XElement("image", "img2")
)
)
);
root.Save(_filePath);
<?xml version="1.0" encoding="utf-8"?>
<MenuItems>
<MenuItem>
<Name>rrrrrr</Name>
<Url>www.this1.com</Url>
<Images>
<image>img1</image>
<image>img2</image>
</Images>
</MenuItem>
<MenuItem>
<Name>ttttt</Name>
<Url>www.this.com</Url>
<Images>
<image>img1</image>
<image>img2</image>
</Images>
</MenuItem>
</MenuItems>
Showing posts with label xml. Show all posts
Showing posts with label xml. Show all posts
Monday, March 15, 2010
Saturday, March 6, 2010
aspx linq get all unique items from an xml
XDocument xDoc = XDocument.Load(Server.MapPath("App_Data/MyCollections.xml"));
List <string>productTypes =
xDoc.Descendants("CollectionItem")
.SelectMany(ci => ci.Descendants("ProductType"))
.Select(pt => pt.Value).Distinct().ToList();
this will return a List<> with all the Distinct ProductType Values under the CollectionItem node of the xml file.
.SelectMany because we want all of the values for ProductType
.Select says we want the Value of the node and only want Distinct ones.
List
xDoc.Descendants("CollectionItem")
.SelectMany(ci => ci.Descendants("ProductType"))
.Select(pt => pt.Value).Distinct().ToList();
this will return a List<> with all the Distinct ProductType Values under the CollectionItem node of the xml file.
.SelectMany because we want all of the values for ProductType
.Select says we want the Value of the node and only want Distinct ones.
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